# What is the average speed of an object that is still at t=0 and accelerates at a rate of a(t) =t^2-1 from t in [2, 3]?

Mar 3, 2016

#### Answer:

${v}_{a v g} = \frac{16}{3} m {s}^{-} 1$

#### Explanation:

The average of a function can be found by integrating the function over the integral.

So, ${v}_{a v g} = {\int}_{2}^{3} a \left(t\right) \mathrm{dt} = {\int}_{2}^{3} \left({t}^{2} - 1\right) \mathrm{dt} = \left({t}^{3} / 3 - t\right) {|}_{2}^{3}$

Placing the limits, you'll be able to solve and see the answer.