What is the average value of the function #h(x) = cos^4 x sin x# on the interval #[0,pi]#? Calculus Derivatives Average Rate of Change Over an Interval 1 Answer Jim H Dec 18, 2016 #2/(5pi)# Explanation: The average value of #cos^4x sinx# on #[0,pi]# is #1/(pi-1) int_0^pi cos^4x sinx dx# Use #u = cosx# to integrate and get # - 1/pi [cosx/5]_0^pi = 2/(5pi)# Answer link Related questions How do you find the average rate of change of a function from graph? How do you find the average rate of change of a function between two points? How do you find the average rate of change of #f(x) = sec(x)# from #x=0# to #x=pi/4#? How do you find the average rate of change of #f(x) = tan(x)# from #x=0# to #x=pi/4#? How do you find the rate of change of y with respect to x? How do you find the average rate of change of #y=x^3+1# from #x=1# to #x=3#? What is the relationship between the Average rate of change of a fuction and derivatives? What is the difference between Average rate of change and instantaneous rate of change? What does the Average rate of change of a linear function represent? What is the relationship between the Average rate of change of a function and a secant line? See all questions in Average Rate of Change Over an Interval Impact of this question 11668 views around the world You can reuse this answer Creative Commons License