# What is the axis of symmetry for the graph of the quadratic equation y=3x^2-12+12x?

Mar 8, 2018

$x = - 2$

#### Explanation:

For any $a {x}^{2} + b x + c$, the axis of symmetry is given by $- \frac{b}{2 a}$

The parabola's equation is $y = 3 {x}^{2} + 12 x - 12$

Method 1

Here, $a = 3$ and $b = 12$, so we input:

$- \frac{12}{2 \left(3\right)}$

$- \frac{12}{6}$

$x = - 2$