# What is the balanced net ionic equation for sodium hydroxide and acetylsalicylic acid?

Feb 11, 2018

${\text{C"_ 6"H"_ 4 "OCOCH"_ 3"COOH" _ ((aq)) + "OH"_ ((aq))^(-)-> "C"_ 6"H"_ 4 "OCOCH"_ 3"COO" _ ((aq))^(-) + "H"_ 2"O}}_{\left(l\right)}$

#### Explanation:

Sodium hydroxide and acetylsalicylic acid neutralize each other in a $1 : 1$ mole ratio to produce aqueous sodium acetylsalicylate and water.

The molecular equation looks like this

${\text{C"_ 6"H"_ 4 "OCOCH"_ 3"COOH" _ ((aq)) + "NaOH"_ ((aq)) -> "C"_ 6"H"_ 4 "OCOCH"_ 3"COONa"_ ((aq)) + "H"_ 2"O}}_{\left(l\right)}$

The complete ionic equation looks like this

${\text{C"_ 6"H"_ 4 "OCOCH"_ 3"COOH" _ ((aq)) + "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-) -> "C"_ 6"H"_ 4 "OCOCH"_ 3"COO" _ ((aq))^(-) + "Na"_ ((aq))^(+) + "H"_ 2"O}}_{\left(l\right)}$

The sodium cations are spectator ions here, i.e. they are present on both sides of the chemical equation, so you can eliminate them

${\text{C"_ 6"H"_ 4 "OCOCH"_ 3"COOH" _ ((aq)) + color(red)(cancel(color(black)("Na"_ ((aq))^(+)))) + "OH"_ ((aq))^(-)-> "C"_ 6"H"_ 4 "OCOCH"_ 3"COO" _ ((aq))^(-) + color(red)(cancel(color(black)("Na"_ ((aq))^(+)))) + "H"_ 2"O}}_{\left(l\right)}$

and write the net ionic equation that describes this reaction.

${\text{C"_ 6"H"_ 4 "OCOCH"_ 3"COOH" _ ((aq)) + "OH"_ ((aq))^(-)-> "C"_ 6"H"_ 4 "OCOCH"_ 3"COO" _ ((aq))^(-) + "H"_ 2"O}}_{\left(l\right)}$