What is the boiling point of a 0.743 m aqueous solution of KCl?

Well, what is the $\text{molal boiling point elevation constant}$ of water?
And note that the $\text{molal boiling point elevation constant}$ relates to the number of particles in solution...a $0.743 \cdot m o l \cdot k {g}^{-} 1$ solution is $1.486 \cdot m o l \cdot k {g}^{-} 1$ with respect to sodium ions, AND chloride ions....i.e. sodium chloride speciates in aqueous solution.