What is the Cartesian form of #(-1,(14pi)/3))#?
1 Answer
Oct 1, 2016
Explanation:
#= (-1) cos((14pi)/3)#
#= -cos((2pi)/3)#
#= -(-1/2)#
#= 1/2#
#= (-1) sin((14pi)/3)#
#= -sin((2pi)/3)#
#= -sqrt3/2#
