Question

What is the Cartesian form of `(-1,(5pi)/4))`?

Answer 1

The Cartesian form is `( (sqrt(2))/2, (sqrt(2))/2 )`.

Explanation:

We can use `x=rcos(theta)` and `y=rsin(theta)` to convert:

`x=-1cos((5pi)/4)=-1(-sqrt(2)/2)=(sqrt(2))/2`
`y=-1sin((5pi)/4)=-1(-sqrt(2)/2)=(sqrt(2))/2`

So the Cartesian form is `( (sqrt(2))/2, (sqrt(2))/2 )`.