What is the Cartesian form of #(-12,(-21pi) /16)#?

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Answer 1 · 2017-04-16T00:37:46

#(6.667,-9.978)#

Use the parametric form to find the #x# value and #y# value.

#x=rcostheta#

#y=rsintheta#

Solve for #x# first:

#x=-12cos(-21pi/16)~~6.667#

Solve for #y#:

#y=-12sin(-21ou/16~~-9.978#

Put this all together to get the cartesian form:

#(6.667,-9.978)#