What is the Cartesian form of #(18,(-11pi)/8))#?
1 Answer
Mar 4, 2016
(-6.888 , 16.63 )
Explanation:
Using the formulae that links Polar to Cartesian coordinates.
#• x = rcostheta#
#• y = rsintheta # here r = 18 and
#theta = (-11pi)/8 #
# x = 18cos((-11pi)/8) ≈ -6.888 #
# y = 18sin((-11pi)/8) ≈ 16.63 #