What is the Cartesian form of #(18,(-34pi)/8)#?

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Answer 1 · 2016-11-16T15:51:30

The cartesian coordinates are #=(9sqrt2,-9sqrt2)#

We use the following equations to transform polar coordinates to cartesian coordinates.

#x=rcostheta#

#y=rsintheta#

The polar coordinates are #(18,(-34pi)/8)#

therefore,

#x=18cos ((-34pi)/8)=18cos ((-2pi)/8)=18*cos(-pi/4)

#x=18*sqrt2/2=9sqrt2#

#y=18*sin((-34pi)/8)=18*sin((-2pi)/8)=18*sin(-pi/4)#

#y=-18*sqrt2/2=-9sqrt2#

#(x,y)=(9sqrt2,-9sqrt2)#