What is the Cartesian form of #(18,(-51pi)/8))#?

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Answer 1 · 2017-07-07T13:15:03

#(6.888, -16.630)#

We're asked to find the Cartesian (rectangular) form of a polar coordinate.

To do this, we can use the equations

#x = rcostheta#

#y = rsintheta#

So

#x = 18cos((-51pi)/8) = color(red)(6.888#

#y = 18sin((-51pi)/8) = color(blue)(-16.630#

The rectangular form is thus

#(color(red)(6.888), color(blue)(-16.630))#