# What is the Cartesian form of ( -2 , (13pi)/3 ) ?

$\left(- 1 , - \sqrt{3}\right)$

#### Explanation:

For the x:

$x = r \cos \theta$

$x = \left(- 2\right) \cdot \cos \left(13 \frac{\pi}{3}\right) = - 1$

$x = - 1$

For the y:

$y = r \cdot \sin \theta$

$y = \left(- 2\right) \cdot \sin \left(13 \frac{\pi}{3}\right) = - \sqrt{3}$

$y = - \sqrt{3}$

the required answer is $\left(- 1 , - \sqrt{3}\right)$