# What is the Cartesian form of (-2,(-161pi) /16)?

Apr 16, 2017

$\left(1.962 , - .390\right)$

#### Explanation:

Use the parametric form to find the $x$ and $y$ components of this polar coordinate. Remember that:

$x = r \cos \theta$

$y = r \sin \theta$

Plug into these formulas:

$x = - 2 \cos \left(- 161 \frac{\pi}{16}\right) \approx 1.962$

$y = - 2 \sin \left(- 161 \frac{\pi}{16}\right) \approx - .390$

We have our $x$ and $y$ component. Now write it as a coordinate:

$\left(1.962 , - .390\right)$