Question

What is the Cartesian form of `( -3 , (25pi)/12 )`?

Answer 1

`(0,-3)`

Explanation:

`x=rcostheta = -3cos((25pi)/2)=-3cos(pi/2 + 12pi)`

`=-3cos(pi/2)=0`

`y=rsintheta=-3sin((25pi)/2) = -3sin(pi/2+12pi)`

`=-3sin(pi/2) = -3`

Hence the Cartesian form of `(-3, (25pi)/12)` is `(0,-3)`.