What is the Cartesian form of #(45,(-15pi)/8)#?

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Answer 1 · 2016-06-10T22:02:18

It is #(41.57, 17.22)#.

Your point is given in coordinates #(r, theta)#.

The conversion is

#x=rcos(theta)#

#y=rsin(theta)#

substituting the numbers

#x=45*cos(-(15pi)/8)\approx41.57#

#y=45*sin(-(15pi)/8)\approx17.22#.