What is the Cartesian form of #( 5, (-7pi)/3 ) #?

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Answer 1 · 2017-12-09T17:39:26

#(5/2,-(5sqrt3) /2 )#

We converting from polar to cartesian:

Polar: #(r, theta) #

Cartesian: #(rcos theta, rsin theta )#

Hence the cartesian will be:

#(5cos((-7pi)/3) , 5sin( (-7pi)/3 ) )#

Hence evaluating on a calculator or using your trig values yields:

#(5/2 , -(5sqrt3) /2 )#