What is the Cartesian form of #( -6 , ( - 9pi)/2 ) #?

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Answer 1 · 2017-11-02T22:31:38

#( 0 , 6 )#

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It can be seen from the diagram that the x coordinate of P is #rcos(theta)# and the y coordinate of P is #rsin(theta)#

So:

#x=rcos(theta)#

#y=rsin(theta)#

From example:

#x= -6cos((-9pi)/2)=0#

#y = -6sin((-9pi)/2)=6#

So Cartesian coordinate is:

#( 0 , 6 )#