What is the Cartesian form of #(-64,(17pi)/12)#?

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Answer 1 · 2017-11-08T18:04:14

#( 16.56 , 61.82 )#

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It can be seen from the diagram that the x coordinate of P is #rcos(theta)# and the y coordinate of P is #rsin(theta)#

So:

#x=rcos(theta)#

#y=rsin(theta)#

From example:

#x=-64cos((17pi)/12)= 16.56#

#y=-64sin((17pi)/12)=61.82#

Cartesian coordinate:

#( 16.56 , 61.82 )#