What is the Cartesian form of #(81,(17pi)/12)#?
1 Answer
Feb 21, 2016
(-20.96 , -78.24 )
Explanation:
Using the formulae that links Polar to Cartesian coordinates.
#• x = rcostheta #
#• y = rsintheta # here r = 81 and
#theta = (17pi)/12 #
#rArr x = 81cos((17pi)/12) = - 20.96# and
#y = 81sin((17pi)/12) = - 78.24#
