# What is the center and radius of the circle with equation #2(x-2)^2+2(y+5)^2=28#?

##### 1 Answer

Jan 25, 2016

Center

Radius:

#### Explanation:

or

Any equation of the form

is a circle with center

So the given equation

is a circle with center

graph{2(x-2)^2+2(y+5)^2=28 [-7.78, 10, -8.82, 0.07]}