# What is the center and radius of the circle with equation (x-2)^2 + (y-5)^2=100?

Jan 31, 2016

centre = (2 , 5 ) and r = 10

#### Explanation:

The standard form of the equation of a circle is :

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$

where (a , b ) is the centre and r , the radius.

compare with : ${\left(x - 2\right)}^{2} + {\left(y - 5\right)}^{2} = 100$

to obtain a = 2 , b = 5 and $r = \sqrt{100} = 10$