# What is the center and radius of the circle with equation x^2 + (y + 6)^2 = 49?

The center is $\left(0 , - 6\right)$ and the radius is $7$.
The equation of a circle with center $\left(a , b\right)$ and radius $r$ in standard form is ${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$.
In this case, $a = 0$, $b = - 6$ and $r = 7$ $\left(\sqrt{49}\right)$.