# What is the center of the circle given by the equation (x - 3)^2 + (y - 9)^2 = 16?

Mar 2, 2018

$\left(3 , 9\right)$

#### Explanation:

The standard form of the equation for a circle is given by:

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

Where:

$\boldsymbol{h}$ is the $\boldsymbol{x}$ coordinate of the centre.

$\boldsymbol{k}$ is the $\boldsymbol{y}$ coordinate of the centre.

$\boldsymbol{r}$ is the radius.

From given equation we can see that the centre is at:

$\left(h , k\right) = \left(3 , 9\right)$