# What is the center of the circle with equation (x + 1)^2 + (y + 3)^2 = 9/4?

$\left(- 1 , - 3\right)$
General equation is ${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$
Where (a,b)is the centre and the radius is $r$
Your radius would be $\frac{3}{2}$ as an aside!