# What is the center of the ellipse represented by (x-6)^2/36+(y+4)^2/16=1?

Sep 28, 2014

The center of the ellipse is (6,-4).

${a}^{2} = 36$
$a = 6$

${b}^{2} = 16$
$b = 4$

The $x$-axis is the major axis . It's vertices/endpoints are $\left(6 \pm a , - 4\right)$.

The $y$-axis is the minor axis . It's vertices/endpoints are $\left(6 , - 4 \pm b\right)$.