Question

What is the center of the ellipse represented by `(x-6)^2/36+(y+4)^2/16=1`?

Answer 1

The center of the ellipse is (6,-4).

`a^2=36`
`a=6`

`b^2=16`
`b=4`

The `x`-axis is the major axis . It's vertices/endpoints are `(6+-a,-4)`.

The `y`-axis is the minor axis . It's vertices/endpoints are `(6,-4+-b)`.