# What is the chemical equation for the ionization of benzoic acid?

${C}_{6} {H}_{5} C {O}_{2} H \left(a q\right) + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s {C}_{6} {H}_{5} C {O}_{2}^{-} + {H}_{3} {O}^{+}$
See this site. A $p {K}_{a} = 4.202$ is reported. For acetic acid, ${H}_{3} C - C {O}_{2} H$, $p {K}_{a} = 4.76$. Can you explain why benzoic acid is a stronger acid than acetic acid?