What is the completely factored form of #2d^4 + 6d^3 -18d^2 -54d #?

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Answer 1 · 2016-10-03T03:17:28

Factor by grouping.

#=2d^4 - 18d^2 + 6d^3 - 54d#

#=2d^2(d^2 - 9) + 6d(d^2 - 9)#

#=(2d^2 + 6d)(d^2- 9)#

#=(2d^2 + 6d)(d + 3)(d - 3)#

#=2d(d + 3)(d + 3)(d - 3)#

#=2d(d+ 3)^2(d - 3)#

Hopefully this helps!