# What is the complex conjugate of 1 + sqrt (-18)?

Apr 18, 2018

$\overline{z} = 1 - \left(\sqrt{18}\right) i$

#### Explanation:

The given number is $z$

$z = 1 + \left(\sqrt{18}\right) i$

To get the complex conjugate just replace $i$ by $- i$.

$\therefore \overline{z} = 1 - \left(\sqrt{18}\right) i$

The property of complex conjugate is that

$z \overline{z} = | z {|}^{2}$