What is the complex conjugate of $sqrt(-13)$ ?

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Answer 1 · 2015-08-26T16:42:26

The complex conjugate of $sqrt(-13)$ is $(-sqrt(-13))$

The complex conjugate of $a+bi$ is $a-bi$

$sqrt(-13)$ can be written as $0+sqrt(13)i$

So its complex conjugate is
$0-sqrt(13)i = -sqrt(13)i = -sqrt(-13)$

What is the complex conjugate of sqrt(-13)sqrt(-13)?