What is the complex conjugate of sqrt(-13)?

Aug 26, 2015

The complex conjugate of $\sqrt{- 13}$ is $\left(- \sqrt{- 13}\right)$
The complex conjugate of $a + b i$ is $a - b i$
$\sqrt{- 13}$ can be written as $0 + \sqrt{13} i$
$0 - \sqrt{13} i = - \sqrt{13} i = - \sqrt{- 13}$