What is the complex conjugate of #sqrt(-13)#?

1 Answer
Aug 26, 2015

Answer:

The complex conjugate of #sqrt(-13)# is #(-sqrt(-13))#

Explanation:

The complex conjugate of #a+bi# is #a-bi#

#sqrt(-13)# can be written as #0+sqrt(13)i#

So its complex conjugate is
#0-sqrt(13)i = -sqrt(13)i = -sqrt(-13)#