Question

What is the complex conjugate of `sqrt(-7)`?

Answer 1

`-isqrt7`

Explanation:

To find a complex conjugate, simply change the sign of the imaginary part (the part with the `i`). This means that it either goes from positive to negative or from negative to positive.

As a general rule, the complex conjugate of `a+bi` is `a-bi`.

Your case is seemingly odd, and may not seem to fit the pattern.

However, `sqrt(-7)=isqrt7`.

As such, this can be written in the `a+bi` form of a complex number as `0+isqrt7`.

Thus, the complex conjugate of `0+isqrt7` is `0-isqrt7`, which equals `-isqrt7`.