What is the conjugate of # 7 - 4i#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Bill K. Dec 3, 2015 #7+4i# Explanation: The complex conjugate of #a+bi# is #a-bi#. Complex conjugates have the cool property that #(a+bi)(a-bi)=a^2-abi+abi-b^2i^2=a^2+b^2=|a+bi|^{2}#. This makes them useful for rewriting quotients #(a+bi)/(c+di)# in the standard form #alpha+beta i#. For example, #(3+2i)/(7-4i)=(3+2i)/(7-4i) * (7+4i)/(7+4i)=(21+12i+14i+8i^2)/(49-16i^2)# #=(13+26i)/(49+16)=13/65+26/65 i=1/5 + 2/5 i# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 4701 views around the world You can reuse this answer Creative Commons License