Question

What is the `cot(pi/2)`?

Answer 1

cot (`pi/2` ) = cos(`pi/2`) / sin(`pi/2`)
`(pi/2)` = `90^o`

so , cot `90^0` = cos `90^o`/sin`90^o`

= 0/1 (cos `90^0` = 0 and sin `90^o` = 1)

= 0

please note : 0/1 = 0
and 1/0 = undefined