What is the cross product of <-3,4, 8 > and <2,-4, 1>?

Mar 12, 2016

$\vec{A} X \vec{B} = 36 \hat{i} + 19 \hat{j} + 4 \hat{k}$
$\vec{A} = {A}_{x} \cdot \hat{i} + {A}_{j} \cdot \hat{j} + {A}_{k} \cdot \hat{k}$
$\vec{B} = {B}_{x} \cdot \hat{i} + {B}_{j} \cdot \hat{j} + {B}_{k} \cdot \hat{k}$
$\text{cross product of two vector is determined by:}$
$\vec{A} X \vec{B} = \hat{i} \left({A}_{y} \cdot {B}_{z} - {A}_{z} \cdot {B}_{y}\right) - \hat{j} \left({A}_{x} \cdot {B}_{z} - {A}_{z} \cdot {B}_{x}\right) + \hat{k} \left({A}_{x} \cdot {B}_{y} - {A}_{y} \cdot {B}_{x}\right)$
$\vec{A} X \vec{B} = \hat{i} \left(4 + 32\right) - \hat{j} \left(- 3 - 16\right) + \hat{k} \left(12 - 8\right)$
$\vec{A} X \vec{B} = 36 \hat{i} + 19 \hat{j} + 4 \hat{k}$