What is the cross product of (- 4 i - 5 j + 2) and (i + j -7k)?

Nov 26, 2016

The cross product is $\left(33 i - 26 j + k\right)$ or $< 33 , - 26 , 1 >$.

Explanation:

Given vector $u$ and $v$, the cross product of these two vectors, $u$ x $v$ is given by:

Where, by the Rule of Sarrus,

This process looks rather complicated but in reality isn't so bad once you get the hang of it.

The vectors $\left(- 4 i - 5 j + 2 k\right)$ and $\left(i + j - 7 k\right)$ can be written as $< - 4 , - 5 , 2 >$ and $< 1 , 1 , - 7 >$, respectively.

This gives a matrix in the form of:

To find the cross product, first imagine covering up the $i$ column (or actually do so if possible), and take the cross product of the $j$ and $k$ columns, similar to as you would using cross multiplication with proportions. In the clockwise direction, multiply the first number by its diagonal, then subtract from that product the product of the second number and its diagonal. This is your new $i$ component.

$\left(- 5 \cdot - 7\right) - \left(1 \cdot 2\right) = 35 - 2 = 33$
$\implies 33 i$

Now imagine covering up the $j$ column. Similarly to above, you take the cross product of the $i$ and $k$ columns. However, this time, whatever your answer is, you will multiply it by $- 1$.

$- 1 \left[\left(- 4 \cdot - 7\right) - \left(2 \cdot 1\right)\right] = - 26$
$\implies - 26 j$

Finally, imagine covering up the $k$ column. Now, take the cross product of the $i$ and $j$ columns.

$\left(- 4 \cdot 1\right) - \left(- 5 \cdot 1\right) = 1$
$\implies k$

Thus, the cross product is $\left(33 i - 26 j + k\right)$ or $< 33 , - 26 , 1 >$.