Question

What is the derivative of `-1/(sin(x)^2)`?

Answer 1

`d/(dx) (-1/sin^2x) = (2cosx)/(sin^3x)`

Explanation:

Based on the chain rule:

`d/(dx) (-1/sin^x) = d/(dsinx) (-1/sin^2x) * (dsinx)/(dx)= 2/(sin^3x)cosx`