Question

What is the derivative of `(2x-1)^3`?

Answer 1

`f'(x) = 6(2x-1)^2`

Explanation:

The derivative of this function involved the power and chain rule, and here is the formula for it

let `f(x) = g^n^n` , then `f'(x) = ng]^(n-1) (g')`

Given `f(x) = (2x-1)^3`

`n= 3` , `g(x) = 2x-1` , `g'(x) = 2`

`f'(x) = 3(2x-1)^2 (2)`

`= 6(2x-1)^2`