What is the derivative of #2x^2+x-1#?
1 Answer
Jan 21, 2016
4x + 1
Explanation:
using : f(x) =
# ax^n color(black)("then") f'(x) = nax^(n-1 )# Apply this to each term in turn to obtain derivative -
Remembering that the derivative of any constant is 0.
# d/dx (2x^2 + x - 1 ) = 4x + 1 #