What is the derivative of 32x?
1 Answer
May 20, 2016
Explanation:
Begin by expressing
32x=32x−1 differentiate using the
power rule
ddx(axn)=naxn−1
⇒ddx(32x−1)=−1×32x−2=−32x2
Begin by expressing
32x=32x−1 differentiate using the
power rule
ddx(axn)=naxn−1
⇒ddx(32x−1)=−1×32x−2=−32x2