# What is the derivative of  -4/x^2?

One law of exponentials states that ${a}^{-} n = \frac{1}{a} ^ n$.
Thus, we can rewrite this as $- 4 {x}^{-} 2$
Using the power rule, which states that for $y = {a}^{n}$, then $y ' = n \cdot {a}^{n - 1}$,
$\frac{\mathrm{dy}}{\mathrm{dx}} = \left(- 2\right) \left(- 4 {x}^{-} 3\right) = 8 {x}^{-} 3 = \frac{8}{x} ^ 3$