What is the derivative of #5 + 6/x + 3/x^2#?
1 Answer
May 8, 2016
Explanation:
I find it easiest to think in terms of the exponent form and use the power rule:
#d/(dx) x^n = n x^(n-1)#
as follows:
#d/(dx) (5+6/x+3/x^2)#
#=d/(dx) (5+6x^(-1)+3x^(-2))#
#=0+6((-1)x^(-2))+3((-2)x^(-3))#
#=-6x^(-2)-6x^(-3)#
#=-6/x^2-6/x^3#