What is the derivative of #b^x# where b is a constant?

1 Answer
Jan 11, 2016

#d/dx[b^x]=b^x*lnb#

Explanation:

First, note that

#b^x=e^ln(b^x)=e^(xlnb)#

This allows us to differentiate the function using the chain rule:

#d/dx[e^(xlnb)]=e^(xlnb)*d/dx[xlnb]#

Just like #d/dx[5x]=5#, #d/dx[xlnb]=lnb#, since #lnb# will always be a constant.

This gives us a derivative of:

#e^(xlnb)*lnb#

Now, recall that #e^(xlnb)=b^x#. This gives us our final, differentiated result:

#d/dx[b^x]=b^x*lnb#