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What is the derivative of $e^{t^{2}}$ $e^(t^2)$ ?

1 Answer

Oct 17, 2015

$2 t e^{t^{2}}$ $2te^(t^2)$

Explanation:

Use the Chain Rule like this:

$\frac{d}{d t} (e^{t^{2}}) = e^{t^{2}} \cdot \frac{d}{d t} (t^{2}) = 2 t e^{t^{2}}$ $d/dt(e^(t^2))=e^(t^2) * d/dt(t^2)=2te^(t^2)$ .

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