What is the derivative of $e^(t^2)$ ?

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Answer 1 · 2016-08-13T09:23:11

$f'(t) = 2te^(t^2)$

$f(t) = e^(t^2)$

$f'(t) = e^(t^2) * d/dt(t^2)$ (Chain rule)

$= 2te^(t^2)$ (Power rule)

What is the derivative of e^(t^2)e^(t^2)?