What is the derivative of $f(x) = cot^2(x)cos(x)$ ?

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Answer 1 · 2016-02-27T06:32:05

Hence $cotx=cosx/sinx$ we have that

$f(x) = cot^2(x)cos(x)=>f(x)=(cosx/sinx)^2*cos(x)=> f(x)=cos^3x/sinx$

Using the quotient rule for differentiation we get

$(df(x))/dx=(cos2x-2)*cot^2x$

What is the derivative of f(x) = cot^2(x)cos(x)f(x) = cot^2(x)cos(x)?