Question

What is the derivative of `f(x) = e^x/lnx`?

Answer 1

`d/dx (e^x/lnx) = (e^x(xlnx-1))/(xln^2x)`

Explanation:

Using the quotient rule:

`d/dx (f/g) = (g * (df)/dx -f *(dg)/dx)/g^2`

we have:

`d/dx (e^x/lnx) = (e^xlnx - e^x/x)/(ln^2x)`

`d/dx (e^x/lnx) = (e^x(xlnx-1))/(xln^2x)`