What is the derivative of $f(x)=x^3-3x$ ?

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Answer 1 · 2016-07-22T23:35:01

$f'(x) = 3(x^2-1)$

The power rule for derivatives tells us that

$d/(dx)[x^n] = n*x^(n-1)$

By applying this rule to this problem, we can see that

$f'(x) = 3x^2 - 3 = 3(x^2-1)$

What is the derivative of f(x)=x^3-3x f(x)=x^3-3x?