Question

What is the derivative of `ln(2x+3)`?

Answer 1

ans.#2/(2x+3)#.

Explanation:

this differentiation is done by cyclic rule:`dz/dx =(dz/dy) (dy/dx)` where
`z` is a function of y & x.
so we do `(d{ln(2x+3)})/dx` =`(d (lnz))/dz` `(dz/dx)` where `z=2x+3`
=`(1/z)` `(d(2x+3))/dx`
=`2/(2x+3)`.