What is the derivative of #ln(sec^2 (x))#?
1 Answer
Mar 10, 2018
The derivative is
Explanation:
We can rewrite using trigonometry and the logarithm laws:
#y= ln(1/cos^2x) = ln(1) - ln(cos^2x) = 0 - ln((cosx)^2) = -2ln(cosx)#
Therefore by the chain rule
#y' = -2(-sinx)/cosx = (2sinx)/cosx = 2tanx#
Hopefully this helps!
