What is the derivative of ln( secx+tanx)? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Sasha P. Oct 20, 2015 f'(x)=secx Explanation: f'(x)=1/(secx+tanx) * (secxtanx+sec^2x) f'(x)=1/(secx+tanx) *secx (tanx+secx) f'(x)=secx Answer link Related questions What is the derivative of f(x)=ln(g(x)) ? What is the derivative of f(x)=ln(x^2+x) ? What is the derivative of f(x)=ln(e^x+3) ? What is the derivative of f(x)=x*ln(x) ? What is the derivative of f(x)=e^(4x)*ln(1-x) ? What is the derivative of f(x)=ln(x)/x ? What is the derivative of f(x)=ln(cos(x)) ? What is the derivative of f(x)=ln(tan(x)) ? What is the derivative of f(x)=sqrt(1+ln(x) ? What is the derivative of f(x)=(ln(x))^2 ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1814 views around the world You can reuse this answer Creative Commons License