Question

What is the derivative of ln(t2 +1)?

Answer 1

`f'(t) = (2t)/(t^2+1)`

Explanation:

I assume `f(t) = ln(t^2+1)`

Apply the chain rule and standard differential of `lng(t)`,
where `g(t) = (t^2+1)`:

`f'(t) = 1/(t^2+1) * d/dt (t^2+1)`

Apply the power rule:

`f'(t) = 1/(t^2+1) * (2t+0)`

`= (2t)/(t^2+1)`